Class 12 Inverse Trigonometry Quiz 1

This is a free quiz/test based on the chapter Inverse Trigonometry from Class 12th Maths.
This quiz covers only the basic concepts of the chapter.
Give this quiz seriously and access you level of preparations.

Welcome to your Inverse Trigonometry Quiz 1

$ 1. \text{What is the principle Domain of } \cos^{-1} x ? $

[-\frac{\pi}{2} , \frac{\pi}{2}]

[-\pi , \pi]

[-1 , 1]

[0 , 1]

None

$ 2. \text{What is the Principal range of } \cot^{-1} x ? $

[-\pi, \pi]

(0, 1)

[0, \pi]

[0, 1]

None

$ 3. \text{ For Suitable Domain } \sin^{-1} (\sin x) = $

1

x

\pi

\frac{\pi}{2}

None

$ 4. \text {For Suitable domain } \sin^{-1} x + \cos^{-1} x = $

\frac{\pi}{2}

1

0

\pi

None

$ 5. \text{Evaluate: } \csc^{-1} 2 $

\frac{\pi}{4}

\frac{\pi}{2}

\frac{\pi}{6}

0

None

$ 6. \text {Evaluate: } \cos^{-1} -\frac{1}{\sqrt{2}} $

\frac{\pi}{4}

\frac{2\pi}{4}

\frac{3\pi}{4}

\frac{\pi}{6}

None

$ 7. \text{What is the principal range of } \sec^{-1} x $ ?

[0, \pi]

\frac{\pi}{2}

[0, \pi] -{\frac{\pi}{2}}

[-\pi, \pi]

None

$ 8. \text {Which of the following function does the graph represents ?} $

y = \sin x

y = \cos x

y = \tan x

y = \cot x

None

$ 9. \text{Which of the following function does the graph represent ?} $

y = \sin^{-1} x

y = \cos^{-1} x

y = \tan^{-1} x

y = \cot^{-1} x

None

$10. \text{Which of the following function does the graph represent ?} $

y = \tan^{-1} x

y = \cos^{-1} x

y = \cot^{-1} x

y = \sec^{-1} x

None

Time's up